← Back to context Comment by tejuis 7 years ago Damn... I mean 2^14 looks good. :) 2 comments tejuis Reply davrosthedalek 7 years ago If you divide by 2^15, you have 1pps, but two states per second (high/low). That might be enough. tejuis 7 years ago Well, division was to be made with a binary counter. They typically work with rising edge clock, and you get a smaller circuit if you have 14 bits compared to 15 bits. I agree that 2^15 can be made to work by using both edges of clock signal.
davrosthedalek 7 years ago If you divide by 2^15, you have 1pps, but two states per second (high/low). That might be enough. tejuis 7 years ago Well, division was to be made with a binary counter. They typically work with rising edge clock, and you get a smaller circuit if you have 14 bits compared to 15 bits. I agree that 2^15 can be made to work by using both edges of clock signal.
tejuis 7 years ago Well, division was to be made with a binary counter. They typically work with rising edge clock, and you get a smaller circuit if you have 14 bits compared to 15 bits. I agree that 2^15 can be made to work by using both edges of clock signal.
If you divide by 2^15, you have 1pps, but two states per second (high/low). That might be enough.
Well, division was to be made with a binary counter. They typically work with rising edge clock, and you get a smaller circuit if you have 14 bits compared to 15 bits. I agree that 2^15 can be made to work by using both edges of clock signal.