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Comment by NikkiA

7 years ago

The proof for that seems to be the existance of 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789abcdefghijklmnopqrstuvwxyz

I guess this comment is now a) vsprintf and b) a gpl violation, too.

Surely your comment isn't a GPL violation! If so then I am going to release a GPL project with every word in the dictionary, so that all comments are GPL violations.