Comment by thaumasiotes

Following up, using this encipherment scheme and starting from a 5-bit seed of 17, you produce values in this sequence:

5, 7, 31, 10, 18, 16, 8, 11, 19, 17, 9, 28, 4, 6, 30, 0, 24, 26, 2, 23, 15, 13, 21, 22, 14, 12, 20, 1, 25, 27, 3, 29.

This might pass an eyeball test for random when viewed as decimal numbers. (Although there sure are a lot of cases where adjacent values are 2 apart!) It looks much worse as binary. Here's every ones digit, all concatenated into a hex string, starting from 17 again:

    e1e01e1f

Let's note that ~(e1e0) = 1e1f. Start from 16 instead and you'd see f0f00f0f. Here are the eights:

    3332bbbc

Individual bits show pretty striking patterns. Since the UUID is reported in hex, that can be mitigated a little by the fact that each hex digit combines four binary columns. But so far it seems pretty likely that this would result in the list of UUIDs looking decidedly nonrandom. There might be quite a bit of shared material between adjacent UUIDs.