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Comment by OutOfHere

6 months ago

Modern embeddings lie on a hypersphere surface, making euclidean equal to cosine. And if they don't, I probably wouldn't want to use them.

1 comment

OutOfHere

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yobbo  6 months ago

True, on a hypersphere cosine and euclidean are equivalent.

But if random embeddings are gaussian, they are distributed on a "cloud" around the hypersphere, so they are not equal.

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