Comment by wizzwizz4
15 days ago
That's confusing because of order of operations. But
while ( *(d++) = *(s++) );
is fairly obvious, so I think it gets a pass.
15 days ago
That's confusing because of order of operations. But
while ( *(d++) = *(s++) );
is fairly obvious, so I think it gets a pass.
No comments yet
Contribute on Hacker News ↗