← Back to context Comment by andrewmcwatters 2 years ago Uninitialized variables are a really common case. 1 comment andrewmcwatters Reply gmueckl 2 years ago The pointer to the uninitialized variable is passed to scanf, which writes a value there unless it encounters an error. The compiler cannot understand this contract from the scanf declaration alone.
gmueckl 2 years ago The pointer to the uninitialized variable is passed to scanf, which writes a value there unless it encounters an error. The compiler cannot understand this contract from the scanf declaration alone.
The pointer to the uninitialized variable is passed to scanf, which writes a value there unless it encounters an error. The compiler cannot understand this contract from the scanf declaration alone.