Comment by mattmcal
15 hours ago
Yes, you just need to maintain a stack of rectangles ordered from lowest to highest. You only ever have to push and pop the top of the stack, so the runtime is O(n).
15 hours ago
Yes, you just need to maintain a stack of rectangles ordered from lowest to highest. You only ever have to push and pop the top of the stack, so the runtime is O(n).
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