Comment by drmpeg

It's theoretically possible.

63.1 dbW = 93.1 dBm (240 watts + 39.3 dB gain)

path loss at 5760 MHz = 283.2 dB (at perigee)

RX gain = 39.3 dB

93.1 - 283.2 + 39.3 = -150.8 dBm

Noise floor at 1.2 dB noise figure and 500 Hz bandwidth = -151.9 dBm

SNR = +1.1 dB (easily detectable by ear with CW).