Decoding Leibniz Notation (2024) 8 hours ago (spakhm.com) 5 comments coffeemug Reply Add to library sixo 2 hours ago Related: "Putting Differentials Back into Calculus " at https://bridge.math.oregonstate.edu/papers/differentials.pdf tptacek 4 hours ago There's other goofy stuff people do with df/dx, right? Like in a u-substitution you literally do "algebra" with it. ajb 2 hours ago If you thought that was goofy, check out "Umbral calculus" https://en.wikipedia.org/wiki/Umbral_calculus ajkjk 2 hours ago well.. no, not exactly. If u = u(x) then du = u'(x) dx holds rigorously, and then you can substitute du/u' = dx in an integral. tptacek 2 hours ago I'm thinking more along the lines of knocking a '2x' out of an integral from d/dx of like 2x^2.
sixo 2 hours ago Related: "Putting Differentials Back into Calculus " at https://bridge.math.oregonstate.edu/papers/differentials.pdf
tptacek 4 hours ago There's other goofy stuff people do with df/dx, right? Like in a u-substitution you literally do "algebra" with it. ajb 2 hours ago If you thought that was goofy, check out "Umbral calculus" https://en.wikipedia.org/wiki/Umbral_calculus ajkjk 2 hours ago well.. no, not exactly. If u = u(x) then du = u'(x) dx holds rigorously, and then you can substitute du/u' = dx in an integral. tptacek 2 hours ago I'm thinking more along the lines of knocking a '2x' out of an integral from d/dx of like 2x^2.
ajb 2 hours ago If you thought that was goofy, check out "Umbral calculus" https://en.wikipedia.org/wiki/Umbral_calculus
ajkjk 2 hours ago well.. no, not exactly. If u = u(x) then du = u'(x) dx holds rigorously, and then you can substitute du/u' = dx in an integral. tptacek 2 hours ago I'm thinking more along the lines of knocking a '2x' out of an integral from d/dx of like 2x^2.
tptacek 2 hours ago I'm thinking more along the lines of knocking a '2x' out of an integral from d/dx of like 2x^2.
Related: "Putting Differentials Back into Calculus " at https://bridge.math.oregonstate.edu/papers/differentials.pdf
There's other goofy stuff people do with df/dx, right? Like in a u-substitution you literally do "algebra" with it.
If you thought that was goofy, check out "Umbral calculus" https://en.wikipedia.org/wiki/Umbral_calculus
well.. no, not exactly. If u = u(x) then du = u'(x) dx holds rigorously, and then you can substitute du/u' = dx in an integral.
I'm thinking more along the lines of knocking a '2x' out of an integral from d/dx of like 2x^2.