Comment by brucehoult
2 days ago
Not really. It looks like that in the C code, but in the generated machine code it'll just be a single `MULH` instruction giving (only) the upper 64 bits of the result, no shift needed.
2 days ago
Not really. It looks like that in the C code, but in the generated machine code it'll just be a single `MULH` instruction giving (only) the upper 64 bits of the result, no shift needed.
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