Comment by dcrazy
5 hours ago
Does the removal of “experimental” now mean that all maintainers are now obligated to not break Rust code?
5 hours ago
Does the removal of “experimental” now mean that all maintainers are now obligated to not break Rust code?
Yeah I was wondering about that one angry bearded guy in that movie. He will be very upset.
Is rust code part of user space?
No maintainer is obligated to not break any part of Linux other than the user space API, there are no stable in-kernel APIs
What they mean is that the Linux kernel has a long-standing policy to keep the whole kernel compilable on every commit, so any commit that changes an internal API must also fix up _all_ the places where that internal API is used.
While Rust in the kernel was experimental, this rule was relaxed somewhat to avoid introducing a barrier for programmers who didn't know Rust, so their work could proceed unimpeded while the experiment ran. In other words, the Rust code was allowed to be temporarily broken while the Rust maintainers fixed up uses of APIs that were changed in C code.
So does this mean that the C developers might need to learn Rust or cooperate more with the rust developer team basically?
2 replies →
There is, I understand, an expectation that if you do make breaking changes to kernel APIs, you fix the callers of such APIs. Which has been a point of contention, that if a maintainer doesn't know Rust, how would they fix Rust users of an API?
The Rust for Linux folks have offered that they would fix up such changes, at least during the experimental period. I guess what this arrangement looks like long term will be discussed ~now.