Comment by bmandale
2 months ago
The checked variant just calls the unchecked, and the panicking variant calls the checked variant. They all need to call unsafe code. See here for details: https://doc.rust-lang.org/nomicon/borrow-splitting.html
2 months ago
The checked variant just calls the unchecked, and the panicking variant calls the checked variant. They all need to call unsafe code. See here for details: https://doc.rust-lang.org/nomicon/borrow-splitting.html
Then you misunderstand what unsafe means in Rust. Every single Rust binary needs to eventually call unsafe code at some layer of the callstack.
Is creating a TCP socket using stdlib functions unsafe? How about writing to a file? Or acquiring a mutex?
I would suggest doing some more reading before chiming in here :)
You have totally misunderstood what the person you are talking with means by unsafe. Perhaps you should resolve that prior to such condescensions.
Indeed I have haha - my bad :)
Easier to lose context with longer comment chains...