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Comment by layer8

7 days ago

> Already, we have a factor of O(log(n)) here.

Doesn’t that mean that O(log(n)) is really O(log²(n))?

2 comments

layer8

Reply

thfuran  7 days ago

You have to define what n is.

  • layer8  6 days ago

    It’s clear from the parent comment that the number of bits needed to represent the input is meant here.

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