Comment by SAI_Peregrinus
3 days ago
If there did, it'd be a distinguisher attack on that CSPRNG. So for a non-broken CSPRNG, the answer is "no", by the definition of "non-broken CSPRNG".
3 days ago
If there did, it'd be a distinguisher attack on that CSPRNG. So for a non-broken CSPRNG, the answer is "no", by the definition of "non-broken CSPRNG".
No comments yet
Contribute on Hacker News ↗