← Back to context Comment by def-pri-pub 5 days ago I did see that, but isn't the vast majority of that page talking about acos() instead? 1 comment def-pri-pub Reply seanhunter 5 days ago That’s equivalent right? acos x = pi/2 - asin xSo if you’ve got one that’s fast you have them both.
seanhunter 5 days ago That’s equivalent right? acos x = pi/2 - asin xSo if you’ve got one that’s fast you have them both.
That’s equivalent right? acos x = pi/2 - asin x
So if you’ve got one that’s fast you have them both.