Comment by Charon77
11 hours ago
x+y = ln(exp(x) * exp(y))
exp(a) = eml(a, 1) ln(a)=eml(1,eml(eml(1,a),1))
Plugging those in is an excercise to the reader
11 hours ago
x+y = ln(exp(x) * exp(y))
exp(a) = eml(a, 1) ln(a)=eml(1,eml(eml(1,a),1))
Plugging those in is an excercise to the reader
You use multiplication in the first line, which you have not expressed through eml yet.
Because of how exp and log turn addition into multiplication and vice versa, once you have the one, you get the other easily.
might need to turn the paper sideways