← Back to context Comment by uecker 13 hours ago It is not even possible to do arithmetic on char in C. 1 comment uecker Reply pjmlp 2 hours ago #include <stdio.h> unsigned int pack_rgb(unsigned char r, unsigned char g, unsigned char b) { return (r << 16) | (g << 8) | b; } unsigned int pack_rgb_arith(unsigned char r, unsigned char g, unsigned char b) { return (r * 65536) + (g * 256) + b; } int main(void) { printf("The color value of (246, 176, 223) is %d\n", pack_rgb(246, 176, 223)); printf("The color value of (246, 176, 223) is %d\n", pack_rgb_arith(246, 176, 223)); } Compiler Explorer link, https://godbolt.org/z/3jExdaTT9I would expect a better comment from someone working on the standard.
pjmlp 2 hours ago #include <stdio.h> unsigned int pack_rgb(unsigned char r, unsigned char g, unsigned char b) { return (r << 16) | (g << 8) | b; } unsigned int pack_rgb_arith(unsigned char r, unsigned char g, unsigned char b) { return (r * 65536) + (g * 256) + b; } int main(void) { printf("The color value of (246, 176, 223) is %d\n", pack_rgb(246, 176, 223)); printf("The color value of (246, 176, 223) is %d\n", pack_rgb_arith(246, 176, 223)); } Compiler Explorer link, https://godbolt.org/z/3jExdaTT9I would expect a better comment from someone working on the standard.
Compiler Explorer link, https://godbolt.org/z/3jExdaTT9
I would expect a better comment from someone working on the standard.