Comment by taegee
8 hours ago
You don't need conditional probability here, as the flips are independent.
It's just p(H)p(T).
And p(H)p(T) = p(T)p(H), thus 2*p(H)p(T) = 2p(1-p).
8 hours ago
You don't need conditional probability here, as the flips are independent.
It's just p(H)p(T).
And p(H)p(T) = p(T)p(H), thus 2*p(H)p(T) = 2p(1-p).
Thats how i noodled thru it internally