Comment by Someone
15 hours ago
FTA: “Under the new semantics, because we only care about logical bit representation (which is endian-agnostic), the operation behaves identically on every target: the first array element becomes the 8 least significant bits”
I wouldn’t call that endian-agnostic. It’s explicitly picking little-endian.
It also makes things look weird for beginners. I know how it works, but in the
test "bitcast [2]u3 to @Vector(3, u2)"
example, turning two 3-bit values [abc def] into three 2-bit values [bc fa de] is way less intuitive than turning it into [ab cd ef].
The behavior is agnostic of the endianness of the target platform.
That's only because we write numbers in big endian.
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