Comment by dataflow
3 hours ago
> I really don't see what's supposedly awful about that loop
The stopping condition is incredibly confusing and non-obvious. Misleading at first glance, in fact. The whole thing is so unidiomatic that I don't think I've even seen it once in my life. It's a better contender for an underhanded C++ code contest than production code.
> but if you want to count down to x instead of 0 you just do i >= x
No you can't. That fails if x == 0. Which perfectly illustrates why using unsigned everywhere isn't so great. And I say this as someone who likes unsigned types and uses them more than average!
Thinking of it as a "stopping condition" is backwards, that part of the loop is called the invariant:
https://en.wikipedia.org/wiki/Loop_invariant
You should think of it as the condition that's true for all iterations, not a one-time event that halts the loop. The loop is short for this:
Which works for both signed and unsigned numbers. It just so happens that for unsigned numbers you can omit the left-hand side of the &&, and for signed numbers you can omit the right-hand side. To support arbitrary lower bounds, you omit neither.