← Back to context Comment by tapirl 2 months ago Maybe I'm wrong, but should it be @clz instead? 2 comments tapirl Reply wrs 2 months ago No, the diagram looks like a binary literal but it's actually backwards from that. Lane 0 becomes the LSB, but that's on the left of the diagram. tapirl 2 months ago Aha, you are right. Smaller indexes are for least-significant bits.
wrs 2 months ago No, the diagram looks like a binary literal but it's actually backwards from that. Lane 0 becomes the LSB, but that's on the left of the diagram. tapirl 2 months ago Aha, you are right. Smaller indexes are for least-significant bits.
No, the diagram looks like a binary literal but it's actually backwards from that. Lane 0 becomes the LSB, but that's on the left of the diagram.
Aha, you are right. Smaller indexes are for least-significant bits.