← Back to context Comment by scythe 4 hours ago This is true for finite sets. For infinite sets, the Sierpinski triangle is a counterexample. 1 comment scythe Reply ky3 4 minutes ago > the Sierpinski triangle is a counterexampleHow so? It's bounded by the large initial triangle. The line containing any two of the vertices doesn't intersect any other point.
ky3 4 minutes ago > the Sierpinski triangle is a counterexampleHow so? It's bounded by the large initial triangle. The line containing any two of the vertices doesn't intersect any other point.
> the Sierpinski triangle is a counterexample
How so? It's bounded by the large initial triangle. The line containing any two of the vertices doesn't intersect any other point.