← Back to context Comment by albert_e 18 hours ago Our 200 digit random number was 199 zeroes followed by a 4- emudhra lawyer maybe (: 10 comments albert_e Reply vbezhenar 17 hours ago Private key size is 384 bits or 116 decimal digits. So 115 zeroes. drno123 16 hours ago You mean, the key was 383 zeros and one “one”, on the third place from the right :) j_maffe 16 hours ago I really wonder if this would/should hold in court. It is ridiculously unlikely yet genuinely possible. kshacker 11 hours ago One of them, sure. 8 of them? j_maffe 10 hours ago At this point we're talking about chances so slim that only philosophy can save the situation. trinari 17 hours ago technically possible alienbaby 16 hours ago Not just technically possible, as likely as getting any other random 116(?) digit number FergusArgyll 15 hours ago Feynman's license plate cdelsolar 9 hours ago i think this oversells the likelihood of it. the probability of any random 116 digit number having its first 115 digits be the number zero is much lower than that of it containing a much higher number of non-zero digits.
vbezhenar 17 hours ago Private key size is 384 bits or 116 decimal digits. So 115 zeroes. drno123 16 hours ago You mean, the key was 383 zeros and one “one”, on the third place from the right :)
drno123 16 hours ago You mean, the key was 383 zeros and one “one”, on the third place from the right :)
j_maffe 16 hours ago I really wonder if this would/should hold in court. It is ridiculously unlikely yet genuinely possible. kshacker 11 hours ago One of them, sure. 8 of them? j_maffe 10 hours ago At this point we're talking about chances so slim that only philosophy can save the situation.
kshacker 11 hours ago One of them, sure. 8 of them? j_maffe 10 hours ago At this point we're talking about chances so slim that only philosophy can save the situation.
j_maffe 10 hours ago At this point we're talking about chances so slim that only philosophy can save the situation.
trinari 17 hours ago technically possible alienbaby 16 hours ago Not just technically possible, as likely as getting any other random 116(?) digit number FergusArgyll 15 hours ago Feynman's license plate cdelsolar 9 hours ago i think this oversells the likelihood of it. the probability of any random 116 digit number having its first 115 digits be the number zero is much lower than that of it containing a much higher number of non-zero digits.
alienbaby 16 hours ago Not just technically possible, as likely as getting any other random 116(?) digit number FergusArgyll 15 hours ago Feynman's license plate cdelsolar 9 hours ago i think this oversells the likelihood of it. the probability of any random 116 digit number having its first 115 digits be the number zero is much lower than that of it containing a much higher number of non-zero digits.
cdelsolar 9 hours ago i think this oversells the likelihood of it. the probability of any random 116 digit number having its first 115 digits be the number zero is much lower than that of it containing a much higher number of non-zero digits.
Private key size is 384 bits or 116 decimal digits. So 115 zeroes.
You mean, the key was 383 zeros and one “one”, on the third place from the right :)
I really wonder if this would/should hold in court. It is ridiculously unlikely yet genuinely possible.
One of them, sure. 8 of them?
At this point we're talking about chances so slim that only philosophy can save the situation.
technically possible
Not just technically possible, as likely as getting any other random 116(?) digit number
Feynman's license plate
i think this oversells the likelihood of it. the probability of any random 116 digit number having its first 115 digits be the number zero is much lower than that of it containing a much higher number of non-zero digits.