Comment by stdbrouw

14 years ago

Because knowing the hardware is, of course, essential to make a well-functioning CRUD app.

If the goal of a CS course is to teach how to make a well-functioning CRUD app, I despair!

  • If the goal of a CS course is to in any way make you reliant on hardware or even physics, I despair.

    What use is physics when you have an infinite tape?

    • If you're a programmer and your program relies on the premise that you have infinite storage then your program is probably not going to work too well. Presumably you're assuming zero seek time too?

      Wasn't that the GP's point that to make the transition from CS to programming some knowledge of physical realities of computers might be useful??

      1 reply →

A physics degree can get you a mid-six-figure job as a quant on Wall Street.

  • Does "mid-six-figure" mean $550k (midpoint of the six-figure range), $300k (ditto but using the geometric mean), or $150k (midpoint of the $100k-$200k range)?

    (My impression is that $150k is a plausible entry-level quant salary, but it seems a bit strange to describe that as "mid-six-figure".)

    • The "x-figure" notation is essentially logarithmic with an offset: "6-figures" = 10^5. Therefore, "mid-six-figures" should be roughly 10^5.5 or $316227.

      1 reply →

    • Curious: how could $150k be mid six-figure? I can accept the roughly 500K or 300K meanings, but if someone told me mid six figure, and they meant roughly $150K, I'd feel like they deliberately mislead or lied about the salary. There's no way I can see a reasonable person expecting $150K when someone is referring to "mid six-figure".