← Back to context Comment by mkoryak 5 years ago thats too enterprisey, at a startup you would write it like this:const charA = (false+"")[1]; 5 comments mkoryak Reply bosswipe 5 years ago That has three constants. mkoryak 5 years ago is this better?const charA = (![]+[])[+!+[]]; mkehrt 5 years ago I cannot even parse this. What is going on here? pdpi 5 years ago [] is still a constant. 1 reply →
bosswipe 5 years ago That has three constants. mkoryak 5 years ago is this better?const charA = (![]+[])[+!+[]]; mkehrt 5 years ago I cannot even parse this. What is going on here? pdpi 5 years ago [] is still a constant. 1 reply →
mkoryak 5 years ago is this better?const charA = (![]+[])[+!+[]]; mkehrt 5 years ago I cannot even parse this. What is going on here? pdpi 5 years ago [] is still a constant. 1 reply →
That has three constants.
is this better?
const charA = (![]+[])[+!+[]];
I cannot even parse this. What is going on here?
[] is still a constant.
1 reply →