Comment by wruza
2 years ago
Not a mathematician, but if there's a computable limit, then why not? E.g. most integers aren't powers of 2, cause lim(n to inf: n / 2^n) = 0
2 years ago
Not a mathematician, but if there's a computable limit, then why not? E.g. most integers aren't powers of 2, cause lim(n to inf: n / 2^n) = 0
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