Comment by neura

I think you are correct, but that's missing the point of the article's content. I'm just a programmer, not a math expert, but I believe these statements are accurate.

1. It's very easy to arrive at the provided values, if you make up some percentages that only go to a single decimal value (1/10th). Though doing so would result in vote counts that are decimal, as well. Then if you just remove the decimal from those values, the given percentages don't change enough to be incorrect, but even when taken to 7 decimal places, the new values are pretty clearly due to the rounding (44.2%: 44.1999989%, 4.6%: 4.6000039%).

2. While yes, the chance of these vote counts coming up in this kind of pattern is similar to the example you provided, even if you were using 0-9 for your example of 6 values, the total combinations is about an order of magnitude less than the total vote count provided here.

3. The finer point made is that there's a very small chance for one of the vote counts to show up as a number that so nicely fits the single decimal percentage, but in this case, all 3 vote counts fit this pattern. The calculations are shown for just 2 of the candidates (so not including the "other") resulting only a 1 in 100 million chance.