You need a rectilinear polygon that tessellates, and has the fewest sides possible to minimize the number of cuts necessary. And it would probably help the cutting if the shape is entirely convex, so that cuts can overshoot a bit without damaging anything.
That suggests a rectangle is the only possible shape.
Rather I wonder why do they even need to cut the extra space, instead of putting something there. I suppose that the structure of the device is highly rectangular from the logical PoV, so there's nothing useful to put there. I suspect smaller unrelated chips can be produced on these areas along the way.
I suspect this would cause alignment issues since you could literally rotate it into the wrong position when doing soldering. That said, perhaps they could get away with cutting less and using more.
That's the idea in the article. Just one big chip. But the reason why it's normally done is that there is a pretty high defect rate, so cutting if every wafer has 1-2 defects you still get (X-1.5) devices per wafer. In the article thy go into how they avoid this problem (I think its better fault tolerance, at a cost)
The cost driver for fabbing out wafers is the number of layers and the number of usable devices per wafer. Higher layer count increases cost and tends to decrease yield, and more robust designs with higher yields increase usable devices per wafer. If circles or other shapes could help with either of those, they would likely be used. Generally the end goal is to have the most usable devices per wafer, so they'll be packed as tightly as possible on the wafer so as to have the highest potential output.
You need a rectilinear polygon that tessellates, and has the fewest sides possible to minimize the number of cuts necessary. And it would probably help the cutting if the shape is entirely convex, so that cuts can overshoot a bit without damaging anything.
That suggests a rectangle is the only possible shape.
If it's just one chip per wafer, why even bother cutting?
Why does it need to tessellate if there's only one chip per wafer?
Rather I wonder why do they even need to cut the extra space, instead of putting something there. I suppose that the structure of the device is highly rectangular from the logical PoV, so there's nothing useful to put there. I suspect smaller unrelated chips can be produced on these areas along the way.
I've never cut a wafer, but I assume cutting is hard and single straight lines are the easiest.
I wonder if you could… just not cut the wafer at all??
I suspect this would cause alignment issues since you could literally rotate it into the wrong position when doing soldering. That said, perhaps they could get away with cutting less and using more.
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That's the idea in the article. Just one big chip. But the reason why it's normally done is that there is a pretty high defect rate, so cutting if every wafer has 1-2 defects you still get (X-1.5) devices per wafer. In the article thy go into how they avoid this problem (I think its better fault tolerance, at a cost)
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Might be jumping in without reading, but the chips you cut out of the wafer have to be delivered to physically different locations.
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The cost driver for fabbing out wafers is the number of layers and the number of usable devices per wafer. Higher layer count increases cost and tends to decrease yield, and more robust designs with higher yields increase usable devices per wafer. If circles or other shapes could help with either of those, they would likely be used. Generally the end goal is to have the most usable devices per wafer, so they'll be packed as tightly as possible on the wafer so as to have the highest potential output.
Right, but they're making just one usable device per wafer already.