Comment by fluoridation 3 months ago No, but *++d = *++s; does. 1 comment fluoridation Reply card_zero 3 months ago That means you have to point just before the source and destination.(Yeah, I forgot the while: while *d++ = *s++;)
card_zero 3 months ago That means you have to point just before the source and destination.(Yeah, I forgot the while: while *d++ = *s++;)
That means you have to point just before the source and destination.
(Yeah, I forgot the while: while *d++ = *s++;)