Comment by chuckadams
25 days ago
That test is short enough to just paste it in here:
begin
real procedure A(k, x1, x2, x3, x4, x5);
value k; integer k;
real x1, x2, x3, x4, x5;
begin
real procedure B;
begin k := k - 1;
B := A := A(k, B, x1, x2, x3, x4)
end;
if k ≤ 0 then A := x4 + x5 else B
end;
outreal(1, A(10, 1, -1, -1, 1, 0))
end
The whole "return by assigning to the function name" is one of my least favorite features of Pascal, which I suppose got it from Algol 60. Where I'm confused though is, what is the initial value of B in the call to A(k, B, x1, x2, x3, x4)? I'm guessing the pass-by-name semantics are coming into play, but I still can't figure out how to untie this knot.
Yeah that's one of the things the test was designed to catch: at that point, B is a reference, to the B that is being defined. Here's a C++ translation from https://oeis.org/A132343 that uses identity functions to make the types consistent:
So in the expression `A(k, B, x1, x2, x3, x4)`, the `B` there is not called, it simply refers to the local variable `B` (inside the function `A`), that was captured by the lambda (by reference): the same B variable that is currently being assigned.
Thanks, that's a bit easier to trace: I think what broke my brain initially is that the x1-x5 parameters were declared as real, when they're apparently nullary functions returning a real. Brings to mind CAFs in Haskell. And all that that in 1960 when most things had less CPU power than the chip in my credit card.