Comment by MForster 16 hours ago It also equals x with appropriate assumptions (x > 0). 4 comments MForster Reply notarget137 14 hours ago Well, then sin(x) = x if x is infinitely small kccqzy 17 minutes ago > Assuming[x == 0, Simplify[Sin[x] == x]]Mathematica returns True. And any middle schooler will also tell you it's true.The only reasonable interpretation of "infinitely small" is that it's zero. exe34 15 hours ago so there's an unconditionally correct answer (it's also equal to abs(x) for x>0), and then there is an answer that is only correct for half the domain, which requires an additional assumption. crubier 12 hours ago sqrt(square(i)) != abs(i)So no, it’s not unconditionally correct either.
notarget137 14 hours ago Well, then sin(x) = x if x is infinitely small kccqzy 17 minutes ago > Assuming[x == 0, Simplify[Sin[x] == x]]Mathematica returns True. And any middle schooler will also tell you it's true.The only reasonable interpretation of "infinitely small" is that it's zero.
kccqzy 17 minutes ago > Assuming[x == 0, Simplify[Sin[x] == x]]Mathematica returns True. And any middle schooler will also tell you it's true.The only reasonable interpretation of "infinitely small" is that it's zero.
exe34 15 hours ago so there's an unconditionally correct answer (it's also equal to abs(x) for x>0), and then there is an answer that is only correct for half the domain, which requires an additional assumption. crubier 12 hours ago sqrt(square(i)) != abs(i)So no, it’s not unconditionally correct either.
Well, then sin(x) = x if x is infinitely small
> Assuming[x == 0, Simplify[Sin[x] == x]]
Mathematica returns True. And any middle schooler will also tell you it's true.
The only reasonable interpretation of "infinitely small" is that it's zero.
so there's an unconditionally correct answer (it's also equal to abs(x) for x>0), and then there is an answer that is only correct for half the domain, which requires an additional assumption.
sqrt(square(i)) != abs(i)
So no, it’s not unconditionally correct either.