Comment by meindnoch 11 hours ago Are you under the impression that CPUs are made exclusively from NAND gates? You can't be serious. 4 comments meindnoch Reply peyton 11 hours ago Might’ve gotten mixed up with CMOS dominance, or I’m ignorant. gugagore 4 hours ago https://en.wikipedia.org/wiki/Mead%E2%80%93Conway_VLSI_chip_...I'm guessing is what they're really talking about. Which is not about NAND gates. marcosdumay 3 hours ago Just to add a bit, but modern digital circuits are almost exclusively MOS, but even the "complementary" bit isn't universal in a large IC. giik 10 hours ago I believe you're not ignorant. But many folks probably lack the process knowledge (CMOS) required to understand why :-)
peyton 11 hours ago Might’ve gotten mixed up with CMOS dominance, or I’m ignorant. gugagore 4 hours ago https://en.wikipedia.org/wiki/Mead%E2%80%93Conway_VLSI_chip_...I'm guessing is what they're really talking about. Which is not about NAND gates. marcosdumay 3 hours ago Just to add a bit, but modern digital circuits are almost exclusively MOS, but even the "complementary" bit isn't universal in a large IC. giik 10 hours ago I believe you're not ignorant. But many folks probably lack the process knowledge (CMOS) required to understand why :-)
gugagore 4 hours ago https://en.wikipedia.org/wiki/Mead%E2%80%93Conway_VLSI_chip_...I'm guessing is what they're really talking about. Which is not about NAND gates.
marcosdumay 3 hours ago Just to add a bit, but modern digital circuits are almost exclusively MOS, but even the "complementary" bit isn't universal in a large IC.
giik 10 hours ago I believe you're not ignorant. But many folks probably lack the process knowledge (CMOS) required to understand why :-)
Might’ve gotten mixed up with CMOS dominance, or I’m ignorant.
https://en.wikipedia.org/wiki/Mead%E2%80%93Conway_VLSI_chip_...
I'm guessing is what they're really talking about. Which is not about NAND gates.
Just to add a bit, but modern digital circuits are almost exclusively MOS, but even the "complementary" bit isn't universal in a large IC.
I believe you're not ignorant. But many folks probably lack the process knowledge (CMOS) required to understand why :-)