Comment by altruios 2 days ago does this assume a maximum of one malicious bookkeeper? 1 comment altruios Reply deno 2 days ago Yes, you need 3f+1, so 4 for f=1, 7 for f=2.https://lamport.azurewebsites.net/pubs/byz.pdf
deno 2 days ago Yes, you need 3f+1, so 4 for f=1, 7 for f=2.https://lamport.azurewebsites.net/pubs/byz.pdf
Yes, you need 3f+1, so 4 for f=1, 7 for f=2.
https://lamport.azurewebsites.net/pubs/byz.pdf