Comment by wrs
5 hours ago
No, the diagram looks like a binary literal but it's actually backwards from that. Lane 0 becomes the LSB, but that's on the left of the diagram.
5 hours ago
No, the diagram looks like a binary literal but it's actually backwards from that. Lane 0 becomes the LSB, but that's on the left of the diagram.
Aha, you are right. Smaller indexes are for least-significant bits.