Comment by WindyTree
1 day ago
I always wondered about breaking down the O( n log n) FFT convolution multiplier into truly discrete pieces to see if you can shrink it more, last I checked languages like Python that use big integers still weren’t using it, and when I implemented it it used complex floats. I don’t see why it couldn’t be THE multiplier, plus it works in constant time with optics.
No comments yet
Contribute on Hacker News ↗