Comment by hedora 1 day ago It is difficult to get to M * N * P control flow edges with O(1) result unwrapping code. 1 comment hedora Reply quotemstr 1 day ago You have exactly as many edges if every fallible routine can throw and every infallible one is marked as nothrow.
quotemstr 1 day ago You have exactly as many edges if every fallible routine can throw and every infallible one is marked as nothrow.
You have exactly as many edges if every fallible routine can throw and every infallible one is marked as nothrow.